मान ज्ञात कीजिए: mathop {lim }limits_{x to 0} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) हम जानते हैं कि $\mathop {\lim }\limits_{	heta 	o 0} \frac{\sin 	heta}{	heta} = 1$.$\mathop {\lim }\limits_{x 	o 0} \frac{\sin 4x}{\sin 2x} =

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) हम जानते हैं कि $\mathop {\lim }\limits_{	heta 	o 0} \frac{\sin 	heta}{	heta} = 1$.$\mathop {\lim }\limits_{x 	o 0} \frac{\sin 4x}{\sin 2x} = \mathop {\lim }\limits_{x 	o 0} \left( \frac{\sin 4x}{4x} \cdot 4x \cdot \frac{1}{\frac{\sin 2x}{2x} \cdot 2x} ight)$$= \mathop {\lim }\limits_{x 	o 0} \left( \frac{\sin 4x}{4x} \cdot \frac{2x}{\sin 2x} \cdot \frac{4x}{2x} ight)$$= \left( \mathop {\lim }\limits_{4x 	o 0} \frac{\sin 4x}{4x} ight) \cdot \left( \mathop {\lim }\limits_{2x 	o 0} \frac{2x}{\sin 2x} ight) \cdot 2$$= 1 \cdot 1 \cdot 2 = 2$.

मान ज्ञात कीजिए: $\mathop {\lim }\limits_{x \to 0} \frac{\sin 4x}{\sin 2x}$

Similar Questions

$\lim _{x \rightarrow 0} \frac{1-\cos x}{x^2} = $

सीमा का मूल्यांकन करें: $\lim _{x \rightarrow 0} \frac{\tan ^2(\pi \sec ^4 x)}{\pi^2 x^4}$

सीमा का मूल्यांकन करें: $\lim _{x \rightarrow 0} \frac{4[\sin (2022 x)-\sin (2020 x)]}{x[\cos (2022 x)+2 \cos (2021 x)+\cos (2020 x)]}$

$\lim_{x \to 0} (\cos ax)^{\csc^2 bx}$ का मान है

$\mathop {\lim }\limits_{x \to 0} \frac{{\cos (\sin x) - 1}}{{{x^2}}} = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module